Data Interpretation and Data Sufficiency
Data Interpretation and Data Sufficiency
8. Total boys taken admission in college B & D together are what percent more than total boys
taken admission in E?
(a) 92.5% (b) 97.5% (c) 99.5% (d) 102.5% (e) 84.5%
From the graphs
Total Girls Boys
A 12000 44% = 5280 6720
B 10500 36% = 3780 6720
C 9000 48% = 4320 4680
D 18000 32% = 5760 12240
E 16000 40% = 6400 9600
Boys B + boys D = 6720 + 12240 =18960
Boys in B and D together more than boys in E = 18960 - 9600 = 9360
Percentage = (9360 / 9600) × 100 = 97.5%,
since 10% of 9600 is 960, 1% of 9600 is 96, 2% of 9600 is 192, 3% of 9600 is 288 and
9600 - 9360 = 240, the percentage lies between 100 - 3 = 97 and 100 - 2 = 98.
From the answer choices it is 97.5
9. 75% and 80% of total girls taken admission in college A & C respectively appeared in an exam
and total students appeared in the exam from A & C is 17910. If total boys appeared in exam
from A is 6048, then find the difference between boys who did not appear in the exam from
college A & C? (a) 438 (b) 428 (c) 418 (d) 408 (e) 448
75/100 = ¾ and 80/100 = ⅘
Girls appeared in the exam from A and C = 5280 × ¾ + 4320 × ⅘ = 3960 + 3456 = 7416
Boys appeared from A and C = 17910 - 7416 = 10494
From C boys appeared = 10494 - 6048 = 4446
Boys not appeared from A = 6720 - 6048 = 672
Boys not appeared from C = 4680 – 4446 = 234 Ans. 672 - 234 = 438
10. Find the ratio of total boys taken admission in college A & B together to total girls taken
admission in D & E together?
(a) 13 : 11 (b) 23 : 19 (c) 21 : 17 (d) 21 : 19 (e) None of these
Boys in A and B = 6720 + 3780 = 10500
Girls in D and E = 5760 + 6400 = 12160
Required ratio = 10500 / 12160
The denominator is higher than the numerator.
But in the answer choices a, b, c, d denominator is less than numerator.
Hence Ans. e
11. If in college F total girls taken admission are 62.5% more than that of total girls taken
admission in C and total boys taken admission in college E & F together is 20580, then find the
percentage of girls taken admission in college F? (a) 33% (b) 43% (c) 39% (d) 37% (e) 45%
Girls in C = 4320, 50% = 43202 = 2160, 12.5% = 43208 = 540, 62.5% = 2160 + 540 = 2700
Girls in F = 4320 + 2700 = 7020
Boys in F = Boys in E and F - Boys in E = 20580 - 9600 = 10980
Total in F = Girls + Boys = 7020 + 10980 = 18000
Girls % in F = 702018000 × 100 = 702 / 18 = 39%
12. In each college there are only three streams (i.e. science, commerce & art) and in college B
the respective ratio of students taking admission in science, commerce & art is 2 : 1 : 4. If out of
total girls taken admission in college B, 40% taken admission in science stream, 25% taken
admission in commerce stream, then find difference between boys taken admission in art &
science streams from college B? (a) 3242 (b) 3464 (c) 3189 (d) 3345 (e) 2964
In B Science Arts
Total 27 × 10500 = 3000 47 × 10500 = 6000
Girls 40100 × 3780 = 1512 35100 × 3780 = 7 × 189 = 1323 (science + commerce = 65%)
Boys 3000 - 1512 = 1488 6000 - 1323 = 4677
Boys difference in art and science = 4677 - 1488 = 3189
13. Find the average number of boys taken admission from all the five given colleges?
(a) 7992 (b) 7982 (c) 6848 (d) 7292 (e) None of these
= 6720+6720+4680+12240+96005 = 399605 = 7992
For a country CO2 emissions ( million metric tons) from various sectors are given in the
following table. Answer the questions (14 to 19) based on the data given:
14. What is the average annual growth rate of CO2 emissions in the Power sector?
(1) ~12.57% (2) ~16.87% (3) ~30.81% (4) ~50.25%
2006 growth rate in Power sector = ((600 - 500) / 500)100 = 20
2007 growth rate in Power sector = ((650 - 600) / 600)100 = 50/6 = ~ 8
2008 growth rate in Power sector = ((700 - 650) / 650)100 = 100/13 = ~ 8
2009 growth rate in Power sector = ((800 - 700) / 700)100 = 100/7 = ~ 14
Average growth rate = ~ ¼ [20+8+8+14] = ~ 50/4 = ~ 12.5 (1)
15. What is the percentage contribution of the power sector to total CO2 emissions in the year
2008? (1) ~30.82% (2) ~41.18% (3) ~51.38% (4) ~60.25%
Note that the total column in the question is not part of the question, we have to find the total
Total in 2008 = 1700
Power sector = 700
We have to find 700/1700 in percentage
10% of 1700 is 170
40% = 170 × 4 = 680
50% = 170 × 5 = 850
So, 700 is just above 40%
From the answer choices Ans (2)
16. In which year, the contribution (%) of industry to total sectoral CO2 emissions was minimum?
(1) 2005 (2) 2006 (3) 2007 (4) 2009
2005 2006 2007 2009
2001030 < 20 3001300 > 20 3201440 > 20 4501950 > 20
10% of 1030 = 103 10% of 1300 = 130 10% = 144 10% = 195
Hence in 2005 it is minimum
17. What is the percentage (%) growth of CO2 emissions from the power sector during 2005 to
2009? (1) 60 (2) 50 (3) 40 (4) 80
(2009 emission in power - 2005 emission in power) / 2005 emission in power = 800-500500
= 300500 = 60% (10% of 500 = 50)
18. Which sector has recorded maximum growth in CO2 emissions during 2005 to 2009?
(1) Power (2) Industry (3) Commercial (4) Agriculture
Power Industry Commercial Agriculture
300500 < 1 250200 = 1.25 170150 = 1.1 12080 = 1.5
Agriculture has recorded maximum growth in emission Ans. (4)
19. By what percentage (%), the total emissions of CO2 have increased from 2005 to 2009?
(1) ~89.32% (2) ~57.62% (3) ~40.32% (4) ~113.12%
(2009 total - 2005 total) / 2005 total = 1950-10301030 = 9201030
10% of 1030 = 103, 90% = 927. Since the numerator is 920 < 927,
from the answer choices, Ans, (1)
The following table shows the percentage profit (%) earned by two companies A and B
during the years 2011 – 15. Answer questions 20 – 22 based on the data contained in the
table:
Profit earned by two companies
Where, percent (%) Profit = Income – ExpenditureExpenditure × 100
20. If the total expenditure of the two companies was Rs.9 lakh in the year 2012 and the
expenditure of A and B were in the ratio 2 : 1, then what was the income of company A in that
year? (1) Rs.9.2 lakh (2) Rs.8.1 lakh (3) 7.2 lakh (4) Rs.6.0 lakh
Expenditure A = ⅔ × 9 = 6 lakh.
2012 profit of A = 35%
35 = Profit percentage = I - 66 × 100
I = 6 × 35100 + 6 = 210/100 + 6 = 2.1 + 6 = 8.1
21. What is the average percentage profit earned by company B?
(1) 35% (2) 42% (3) 38% (4) 40%
Total profit % of B = 30 + 40 + 35 + 50 + 35 = 190
Average = 1905 = 38
22. In which year, the percentage profit earned by company B is less than that of company A?
(1) 2012 (2) 2013 (3) 2014 (4) 2015
From the table it is in 2013
Question numbers 23 to 28 are based on the tabulated data given below:
A company has 20 employees with their age (in years) and salary (in thousand rupees per month)
mentioned against each of them:
23. Classify the data of age of each employee in class intervals of 5 years. Which class interval of
5 years has the maximum average salary?
(1) 40 – 45 years (2) 45 – 50 years (3) 50 – 55 years (4) 35 – 40 years
Maximum salary 60, next 55 and 50 - 55 years salary are 45, 60, 55, so average salary 53.3
and all other salaries are < 50, hence the remaining average are < 50. Ans. (3)
Aliter:
Age Salary Average
35 - 40 40, 35 < 50
40 - 45 35, 35, 45, 50, 30, 45, 50 < 50
45 - 50 50 = 50
50 - 55 45, 60, 55 > 50
Ans. (3)
24. What is the average salary (in thousand per month) in the age group 40 – 50 years?
(1) 42.5 (2) 40.5 (3) 36.5 (4) 35
Salary of the age 40 - 50 are 35, 35, 50, 30, 45, 50, 45, 50
Average = Total / 8 = 3408 = 42.5
25. What is the fraction (%) of employees getting a salary ≥ 40,000 per month?
(1) 50% (2) 35% (3) 32% (4) 45%
Number of employees getting salary ≥ 40,000 = 9 Ans. = 920 × 100 = 45%
26. What is the fraction of employees getting a salary less than the average salary of all the
employees? 1) 50% (2) 55% (3) 47% (4) 45%
Total salary = 775
Average salary = 77520 = 38.75
Number of employees getting salary < 38.75 = 11
Required fraction = 1120 × 100 = 55%
27. What is the average age of the employees?
(1) 38.6 years (2) 47.2 years (3) 45.3 years (4) 40.3 years
Total age = 806
Average age = 80620 = 40.3
28. What is the frequency (%) in the class interval of 30 – 35 years?
(1) 25% (2) 30% (3) 35% (4) 20%
Number of employees in age 30 - 35 = 7
Required frequency % = 720 × 100 = 35%
Given below in the table is the decadal data of population and Electrical Power Production
of a country.
Based on the above table, answer the questions from SI.No.29 to 34.
29. Which decade registered the maximum growth rate (%) of population?
(1) 1961 -71 (2) 1971 - 81 (3) 1991 - 2001 (4) 2001 – 2011
1961 - 1971 321 × 100 = 17 × 100 14.28%
1971 - 1981 324 × 100 = 18 × 100 12.5%
1991 - 2001 230 × 100 = 115 × 100 6.66%
2001 - 2011 332 × 100 9.36%
Clearly 321 is larger than all the others, hence Ans. (1), the exact % are needed only for the
next question
30. Average decadal growth rate (%) of population is :
(1) ~12.21% (2) ~9.82% (3) ~6.73% (4) ~5%
1951 - 1961 120 × 100 5%
1981 - 1991 327 × 100 = = 19 × 100 11.11%
Average growth rate = = 14.28 + 12.5 + 6.66 + 9.36 + 5 + 11.116 = 58.916 = 9.818%
Ans. (2)
31. Based on the average decadal growth rate, what will be the population in the year 2021?
(1) 40.34 million (2) 38.49 million (3) 37.28 million (4) 36.62 million
Growth in 2021 = 9.82100 × 35 = 0.491× 7 = 3.437
Population in 2021 = 35 + 3.437 = 38.437 Ans. (2)
32. In the year 1951, what was the power availability per person?
(1) 100 W (2) 200 W (3) 400 W (4) 500 W
Population in 1951 = 20 million
Power generation in 1951 = 10 GW = 10 × 1000 million watt
Power availability per person in 1951 = 1000020 = 500 watt
33. In which decade, the average power availability per person was maximum?
(1) 1981 - 1991 (2) 1991 - 2001 (3) 2001 - 2011 (4) 1971 - 1981
It is clear from the table that average per person availability is maximum in 2001 - 2011
34. By what percentage (%) the power production increased from 1951 to 2011?
(1) 100% (2) 300% (3) 600% (4) 900%
(2011 power production - 1951 production) / 1951 production × 100 = 100 - 1010 × 100 = 900%
35. Consider the following table:
Year : 2008 2009 2010 2011
Sales (crores) : 15 25 32 54
The year in which the sale registered a sharp increase over that of the preceding year is
(a)2008 (b)2009 (c)2010 (d)2011
Sale increase over that of the preceding year are 1015, 725, 2232
Clearly 725 is the smallest and 1015 = 2030, hence 2232 is the largest, which corresponds to the year
2011
The following table shows the number of people in different age groups who responded to a
survey about their favourite style of music. Use this information to answer the Questions
36 – 38 that follow to the nearest whole percentage:
Total 33 33 68 134
36. Approximately what percentage of the total sample were aged 21 – 30?
(1) 31% (2) 23% (3) 25% (4) 14%
Total aged 21 - 30 / Over all total = 33134
10% of 134 = 13.4, 1% = 1.34, 20% = 26.8, 5% = 6.7
Ans 25%
37. Approximately what percentage of the total sample indicates that Hip-Hop is their favourite
style of music?
(1) 6% (2) 8% (3) 14% (4) 12%
Hip-Hop total / overall total = 16134
10% of 134 = 13.4, 1% = 1.34 Ans. 12%
38. What percentage of respondents aged 31 + indicated a favourite style other than classical
music?
(1) 64% (2) 60% (3) 75% (4) 50%
(Total of age above 31 - number of respondents for classical music) / Total of age above 31
= (68 - 17) /68 = 51 / 68 = ¾ = 75%
Data Sufficiency
Directions (39 – 44): The questions below consist of a question followed by two statements
labelled I and II. You have to decide whether these statements are sufficient to answer the
question. Give answer
(a) If statement I alone is sufficient to answer the question but statement II alone is not
sufficient to answer the question.
(b) If statement II alone is sufficient to answer the question but statement I alone is not
sufficient to answer the question.
(c) If you can get answers from I and II together.
(d) If both statements taken together are not sufficient.
39. In a bag there are coins of Re.1, 50 paise and 25 paise. Find the number of 50 paise coins.
I.There are ten rupees in the form of 25 paise coins.
II. There are 73 rupees in the bag in all.
By I, Number of 25 paise coins = 1000 / 25 = 40
By I and II, 73 - 10 = 63 rupees in the form of 1 Re and 50 paise.
The above two taken together are not sufficient to find the number of 50 paise coins.
Ans. (d)
40. Is the two digit positive integer n divisible by 18?
I.When n is divisible by 3 the remainder is 2.
II. When n is multiplied by 3 we get the result in 3 digits.
By I, n is not divisible by 3 and hence not divisible by 18, so I alone is sufficient to answer.
All n greater than 33 satisfy II, but there are integers greater than 33 which are divisible by
18 and which are not divisible by 18.
Hence II alone is not sufficient to answer.
Ans. (a)
41. What is the value of a two digit number?
I.The sum of the two digits is four.
II. The difference between the two digits is two.
(d), since by I and II the digits are 1 and 3, but the value can be 13 or 31
42. Is x greater than y?
I.x is greater than 145.
II. y is greater than 140.
(d), since if y also is greater than 145, then both I and II are not sufficient to give the answer
43. A goat is placed for grazing inside a triangular field and is tethered to one of the vertices of
the field by a rope. What would be the area over which the goat can graze inside the field?
I.The rope is 7m long
II. The field is equilateral of 10m.
The goat can graze in the area of the field which is the sector of the circle centre at the
vertex of the triangle where it is tethered and radius the length of the rope.
By I, the radius = 7.
By II, each angle of the triangle = 60o and each of the sides of the triangle = 10.
Hence the angle of the sector of the circle is 60o and the radius is 7 and hence the area of the
sector of the circle can be calculated by both I and II. Ans. (c)
44. Suresh was 29 years old when his son Ramesh was born. What is the present age of Ramesh?
I.The sum of their ages now is 73 years.
II. The difference of their ages now is known.
Given S = R + 29 when R is born.
Hence S = R + 29 always.
By I, S + R = 73. Hence R can be obtained.
So, I alone is sufficient to answer.
But II is S - R is known now.
But S - R value is a constant which will not change. Hence II is the same as the given one
S - R = 29.
From this alone R can't be obtained. So,bII alone is not sufficient to answer. Ans. (a)
Comments
Post a Comment